1) (b^2-7)(b^2+7)(b^4+49)= 2) (a^2-9)(a^2+9)(a^4+81)= - вопрос №1272744922929481332326312604 от Катер007 26.11.2020 12:26

Question

Алгебра: 1) (b^2-7)(b^2+7)(b^4+49)= 2) (a^2-9)(a^2+9)(a^4+81)= 3) (n^3-2m)(n^3+2m)(n^6+4m^2)= 4) (3x-y^2)*(3x+y^2)(9x^2+y^4)=

Катер007 · Answer

1) (b^2-7)(b^2+7)(b^4+49)=2) (a^2-9)(a^2+9)(a^4+81)=
3) (n^3-2m)(n^3+2m)(n^6+4m^2)=
4) (3x-y^2)*(3x+y^2)(9x^2+y^4)=

1) (b^2-7)(b^2+7)(b^4+49)=(b^4-49)(b^4+49)=(b^8+49²)=b^8+2401

2) (a^2-9)(a^2+9)(a^4+81)=(a^4-81)(a^4+81)=(a^8-81²)=(a^8-6581)
3) (n^3-2m)(n^3+2m)(n^6+4m^2)=(n^6-4m²)(n^6+4m²)=n^12-16m⁴)
4) (3x-y^2)(3x+y^2)(9x^2+y^4)=(9x^2-y^4)(9x^2+y^4)=(81x^4+y^8)