1) (x+10)^2+(x+6)^2=2x^2 2) -2х^2+3x-4=-x^2-x+(2-x^2) - вопрос №1102622222234222342405681373 от hilton1 19.09.2022 19:30

Question

Алгебра: 1) (x+10)^2+(x+6)^2=2x^2 2) -2х^2+3x-4=-x^2-x+(2-x^2) 3) -4x^2-4x=0

hilton1 · Answer

1) x^2 + 20x + 100 + x^2 + 12x + 36 = 2x^2
2x^2 - 2x^2 + 32x = - 136
32x = - 136
x= - 4,25

2) - 2x^2 + 3x - 4 + x^2 + x - 2 + x^2 =0
- 2x^2 + 2x^2 + 4x - 6 =0
4x = 6
x= 1,5

3) - 4x^2 - 4x = 0
x^2 + x = 0
x( x + 1) = 0
x = 0
x + 1 =0
x = - 1