1) y=√4+y + 1/√15-5y 2)16/x^2-16 + x/x+4 = 2/x-4 - вопрос №14115521621642436010605415586398 от yuliya91 28.08.2020 09:23

Question

Алгебра: 1) y=√4+y + 1/√15-5y 2)16/x^2-16 + x/x+4 = 2/x-4 3)60/10-x - 60/x = 5 4)1/x-1 + 1/x^2-1 = 5/8

yuliya91 · Answer

1) y=√4+y + 1/√15-5y√4+√15/15=5y(√60+√15)=5y*15=75y√15(√4+1)=75y√4+1=√15*5yy=(√4+1) / (√15*5)2)16/x^2-16 + x/x+4 = 2/x-43)60/10-x - 60/x = 54)1/x-1 + 1/x^2-1 = 5/8...