Объяснение:
–(2x+3)²+(x+5)(2x+5)=16
–(4х²+12х+9)+(2х²+5х+10х+25)=16
–4х²–12х–9+2х²+5х+10х+25=16
–2х²+3х+16=16
–2х²+3х=0
а=–2;
b=3
с=0
Д= 3²–4*(–2)*0= 9–0= 9
х(1)=
х(2)=
Объяснение:
–(2x+3)²+(x+5)(2x+5)=16
–(4х²+12х+9)+(2х²+5х+10х+25)=16
–4х²–12х–9+2х²+5х+10х+25=16
–2х²+3х+16=16
–2х²+3х=0
а=–2;
b=3
с=0
Д= 3²–4*(–2)*0= 9–0= 9
х(1)=![\frac{ - 3 + \sqrt{9} }{ - 4} = \frac{ - 3 + 3}{ - 4} = 0](/tpl/images/1088/6236/c7a20.png)
х(2)=![\frac{ - 3 - \sqrt{9} }{ - 4} = \frac{ - 3 - 3}{ - 4} = \frac{ - 6}{- 4} = \frac{3}{2} = 1.5](/tpl/images/1088/6236/9e29b.png)