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cooldude28
cooldude28
31.03.2023 09:56 •  Алгебра

Двоє робітників,працюючи разом,закінчили роботу задва дні. за скільки днів виконає цю роботу кожен із них,працюючи окремо,коли відомо,що якби перший працював 2дні ,а другий 1 день,то разом вони б виконали 5/6всієї роботи

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Ответ:
skymiss
skymiss
02.09.2022 12:11

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Must Waste More Time...

0,0(0 оценок)
Ответ:
raxievali
raxievali
02.08.2020 17:21
Б) f(x)=4-2x
f`(x)=(4-2x)`=(4)`-(2x)`=0-2·(x)`=-2·1=-2
Применили правила:
производная суммы( разности) равна сумме( разности) производных
Производная постоянной (C)`=0
Постоянный множитель можно вынести за знак производной
(х)`=1
Производная принимает во всех точках одно и то же значение (-2)
f`(0,5)=f`(-3)=-2

в) f(x)=3x-2
f`(x)=(3x-2)`=(3х)`-(2)`=3·(x)`-0=3·1=3
Применили правила:
производная суммы( разности) равна сумме( разности) производных
Производная постоянной (C)`=0
Постоянный множитель можно вынести за знак производной
(х)`=1
Производная принимает во всех точках одно и то же значение (3)
f`(5)=f`(-2)=3
0,0(0 оценок)
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