1) AB = A + B
2) BC = 3*(B + C) = 3B + 3C
3) AC = 2A + 2C
C = (2A + 2C) : A
B = (3B + 3C) : C
A = AB - B
A*B \ C = (AB - B)*(3B + 3C) \ C \ C = 3AB^2 + 3ABC - 3B^2 - 3BC \ C ^2
1) AB = A + B
2) BC = 3*(B + C) = 3B + 3C
3) AC = 2A + 2C
C = (2A + 2C) : A
B = (3B + 3C) : C
A = AB - B
A*B \ C = (AB - B)*(3B + 3C) \ C \ C = 3AB^2 + 3ABC - 3B^2 - 3BC \ C ^2