f'(x)=3x^2-4x+1
3x^2-4x+1=0
D=16-12=4
x1=(4-2)/6=1/3 y1=1/27-2/9+3=(1-6+81)/27=76/27
x2=(4+2)/6=1 y2=1-2+3=2
f'(x)=3x^2-4x+1
3x^2-4x+1=0
D=16-12=4
x1=(4-2)/6=1/3 y1=1/27-2/9+3=(1-6+81)/27=76/27
x2=(4+2)/6=1 y2=1-2+3=2