ответ:[-7/24π+πn/2; π/24+πn/2],n∈z
Объяснение: 2sin2x·cos2x ≤1/4 ·2;
sin4x ≤1/2;
-7/6 π+2πn≤4x≤π/6 +2πn, n∈z;
-7/24 π+πn/2≤x≤π/24+πn/2,n∈z;
ответ:[-7/24π+πn/2; π/24+πn/2],n∈z
Объяснение: 2sin2x·cos2x ≤1/4 ·2;
sin4x ≤1/2;
-7/6 π+2πn≤4x≤π/6 +2πn, n∈z;
-7/24 π+πn/2≤x≤π/24+πn/2,n∈z;