(2c–5e)(d+3)(d–2)
Объяснение:
5ed–12c+30e+2cd²–5ed²=
=2cd–5ed–12c+30e+2cd²–5ed²=
=d(2c–5e)–6(2c–5e)+d²(2c–5e)=
=(2c–5e)(d–6+d²)=(2c–5e)(d+3)(d–2)
(2c–5e)(d+3)(d–2)
Объяснение:
5ed–12c+30e+2cd²–5ed²=
=2cd–5ed–12c+30e+2cd²–5ed²=
=d(2c–5e)–6(2c–5e)+d²(2c–5e)=
=(2c–5e)(d–6+d²)=(2c–5e)(d+3)(d–2)