применим теоему Виета 1/x1x2=c1 x1x2=3 c1=1/3
1/x1+1/x2=(x1+x2)/x1x2=9/3=3 b1=-3
x^2-3x-1/3=0
x1+x2=9 x1*x2=3
1/x1+1/x2=x1+x2/x1*x2=9/3=3
1/x1*1/x2=1/x1*x2=1/3
x^2-3x+1/3=0
3x^2-9x+1=0
применим теоему Виета 1/x1x2=c1 x1x2=3 c1=1/3
1/x1+1/x2=(x1+x2)/x1x2=9/3=3 b1=-3
x^2-3x-1/3=0
x1+x2=9 x1*x2=3
1/x1+1/x2=x1+x2/x1*x2=9/3=3
1/x1*1/x2=1/x1*x2=1/3
x^2-3x+1/3=0
3x^2-9x+1=0