а)
3ab+6a² =3a(b+2a)
в)
2x²‐2y²-3y+3x=2(x²-y²)+3(x-y)=2(x-y)(x+y)+3(x-y)=(x-y)[2(x+y)+3]=(x-y)(2x+2y+3)
б)
9x²‐25 =(3x-5)(3x+5)
а)
3ab+6a² =3a(b+2a)
в)
2x²‐2y²-3y+3x=2(x²-y²)+3(x-y)=2(x-y)(x+y)+3(x-y)=(x-y)[2(x+y)+3]=(x-y)(2x+2y+3)
б)
9x²‐25 =(3x-5)(3x+5)