Решите, квадратное уравнение 3x²-124x-84=0

[tex]3 {x}^{2} - 124x - 84 = 0 \\ d = 15376 + 4 \times 3 \times 84 = 16384 \\ x1 = \frac{124 - 128}{6} = - \frac{4}{6} = - \frac{2}{3} \\ x2 = \frac{124 + 128}{6} = \frac{252}{6} = 42

Д= -124^2 - 4ас= 15 376 + 1008= 128^2

Х1= -b-128/2a=124-128/6 = -4/6=-2/3

X2=124+128/6= 42