Решите уравнение : (4х+1)^2=5y (x+4)^2=5y - вопрос №41254252772473 от born380111 14.05.2021 04:54

Question

Алгебра: Решите уравнение : (4х+1)^2=5y (x+4)^2=5y

born380111 · Answer

5Y = 5Y
( 4X + 1)^2 = ( X + 4)^2

16X^2 + 8X + 1 = X^2 + 8X + 16
16X^2 - X^2 + 8X - 8X = 16 - 1
15X^2 = 15
X^2 = 1
X1 = 1
X2 = - 1

5Y = X^2 + 8X + 16
5Y = 1 + 8 + 16 = 25
Y1 = 5

5Y = 1 - 8 + 16 = 9
Y2= 9/5 = 1,8

ответ ( 1 ; 5 ) ; ( - 1 ; 1,8 )