Tg31п/6= (2 tgп/6 - tgп/3): cosп/6= ctg13п/4= cos19п/3= - вопрос №31626361341931500894 от akselroddasha 25.04.2021 02:15

Question

Алгебра: Tg31п/6= (2 tgп/6 - tgп/3): cosп/6= ctg13п/4= cos19п/3=

akselroddasha · Answer

Tg31П/6=tg(31pi/6-5pi)=tgpi/6=1/sqrt(3) (2 TgП/6 - TgП/3): cosП/6=(2sqrt(3)-sqrt(3)/3)*2/sqrt(3)=4-2/3=10/3 Ctg13П/4=ctg(13pi/4-3pi)=ctgpi/4=1 cos19П/3=cos(19pi/3-6pi)=cospi/3=1/2...