Встандартный вид: 3(х+1)²=2х+2 (х+3)(х-1)=2х(х-2)+5 - вопрос №3122312258146618 от tatarchenko04 30.11.2021 19:05

Question

Алгебра: Встандартный вид: 3(х+1)²=2х+2 (х+3)(х-1)=2х(х-2)+5

tatarchenko04 · Answer

3(x^2 + 2x + 1) = 2x + 23x^2 + 6x + 3 = 2x + 23x^2 + 4x + 1 = 0D = 4^2 - 4 * 3 * 1 = 16 - 12 = 4√D = √4 = 2x1 = (-4 + 2) / 6 = -2 / 6 = - 1/3x2 = (-4 - 2) / 6 = - 6 / 6 = -1ответ: -1.(x + 3)(x - 1) = 2x(x - 2) + 5...x^2 - 6x + 8 = 0D = 6^2 - 4*1*8 = 36 - 32 = 4√D = √4 = 2x1 = (6 + 2) / 2 = 8 / 2 = 4x2 = (6 - 2) / 2 = 4 / 2 = 2ответ: 2....