Выполните возведение в степень (x^2-y^2)^3 2) (2m^2-3n^2)^3

1)(x²-y²)³ = (х²)³ + 3·(х²)²·(-у²) + 3·х²·(-у²)² + (-у²)³ =
= х⁶- 3·х⁴·у² + 3·х²·у⁴ - у⁶

2) (2m²-3n²)³ = (2m²)³ + 3·(2m²)²·(-3n²)+3·(2m²)·(-3n²)²+(-3n²)³=
=8·m⁶ - 36·m⁴·n² + 54·m²·n⁴ - 27·n⁶