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zippops
zippops
02.04.2020 02:16 •  Английский язык

3. Match the correct item. 1) My friend's / friends' name is Alex.
2) This is the dogs / dog's toy.
3) The children's / childrens' school is next to the shop.
4) Look at Mary's / Mary new dress.
5) He is Meg / Meg's friend.
6) This is Paul's and Charles / Paul and Charles's house.
7) These are the boys' / boys balls.
8) My father's / father bike is black.
9) The fox / fox's tail is long. 10) This is my mother's / my mother car.


3. Match the correct item. 1) My friend's / friends' name is Alex. 2) This is the dogs / dog's toy.

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Ответ:
Moonlight06
Moonlight06
03.04.2022 13:40
All around the world there are many natural habitats that are 1) in danger of disappearing. 2) When a habitat becomes endangered, the plants and animals that make their homes there are also endangered. People destroy wild places everywhere. Why? Simply 3) because there are too many of us! We need room for houses, clean water and large areas for building factories. Sounds selfish, doesn't it? It does, but 4) there are ways you can help. Firstly, find out if there are any organisations in your area that try 5) to protect natural natural habitats and get involved. Or, if you really don't have enough time to join one 6) of these organisations, why not donate some money to help them with 7) their cause? Finally, you could write a letter to your mayor or MP protesting that a natural habitat in 8) your area is endangered and needs protection. You can even start a petition, get all your friends and neighbours to sign it and then give it to your local council. Don't forget - we can all do something to help.
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Ответ:
професор3814
професор3814
05.05.2023 02:46
Сначала формулы . затем формулы двойного угла sin2α=2sinαcosα cos2α=cos²α-sin²α=cos²α-(1-cos²α)=2cos²α-1⇒  2cos²α=1+cos2α cos2α=cos²α-sin²α=1-sin²α-sin²α=1-2sin²α⇒  2sin²α=1-cos2α а) сos75°cos105°=cos(90°-15°)·cos(90°+15°)== sin15°(-sin15°)=-sin²15°=-(1-cos30°)/2=(cos30°-1)/2= ((√3/2)-1)/2=0,25√3-0,5б) sin75°sin15°=°sin(90°-15°)sin15°=cos15° sin15°=sin30°/2=1/4=0,25в) sin105°cos15°=sin(180°-75°)cos15°=sin75°cos15°=sin(90°-15°)cos15°=cos15°cos15°=(1+cos30°)/2=(1+(√3/2))/2=0,5 +0,25√3 2 способ формулы cosα·cosβ=0,5cos(α-β)+0,5cos(α+β) sinα·sinβ=0,5cos(α-β)-0,5cos(α+β) sinα·cosβ=0,5sin(α+β)+0,5sin(α-β) а) сos75°cos105°=0,5cos(75°-105°)+0,5cos(75°+105°)=0,5cos(-30°)+0,5 cos180°==0,5· √3/2+0,5·(-1)=0,25√3-0,5б) sin75°sin15°=0,5cos(75°-15°)-0,5cos(75°+15° )=0,5cos60°-0,5 cos90°=0,5·0,5=0,25в) sin105°cos15°=0,5sin(105°+15°)+0,5sin(105°-15°)= =0,5sin120°+0,5sin90°==0,5 sin(180°-60°)+0,5·1=0,5 sin 60°+0,5=0,25√3+0,5
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