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dkrechetov85

К раствору серной кислоты объемом 400 мл плотностью 1,1 г/мл с массовой долей серной кислоты 0,15 добавили воду массой 60 г.

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Ответ:
valeria2106
valeria2106
17.04.2019 07:20
найдем массу первого раствора: m = Vp
m = 400∙1,1 = 440 г
440∙0,15+ 60∙0% = 500х
66=500х
Х=0.132 или 13,2%
0,0(0 оценок)
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