На якій відстані від центра Землі супутник (так званий синхронний супутник), зможе «висіти» над однією і тією самою точкою земної поверхні (g 10 м/с2 )" .
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m = 5,1 т = 5100 кг
L = 248 см = 2,48 м
d = 25 см = 0,25 м
Площадь соприкосновения гусеницы трактора с землёй равна произведению длины соприкасающейся части гусеницы и её ширины:
L*d = S1
Гусениц у трактора две, тогда общая площадь соприкосновения будет:
So = 2*S1 = 2*L*d
Давление равно отношению силы к площади поверхности, к которой приложена сила:
p = F/S
Сила, с которой трактор давит на землю - это его вес. А его вес равен силе тяжести:
F = P = mg
Тогда давление будет:
р = F/S = mg/So = mg/2S1 = 5100*10/2*2,48*0,25 = 41129,03... = 41129 Па = 41,129 кПа = 41 кПа
ответ: примерно 41 кПа или по 20,5 кПа на каждую из гусениц.
Объяснение:
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