Визначити за який час електричний чайник з ккд - 80% передасть посудині з водою 2000000дж теплоти, якщо потужність чайника 2000вт.скільки теплоти чайник втратить у навколишньому середовищі?
аквпикнр5е6пкраеркврин526462еач5кигач5а. 256н6е6а5крнпмннмн7м6пм6пм6пир7ир6мр6м6емнпмнпмнпву4а6ем4аеRead the text again and write next to the sentences True/False according to the text.
1. She looks after the big animals.
2. Her favorite animals are the tigers.
3. There are four elephants at the zoo.
4. Molly gets up at 6 o'clock.,
5. The lions eat salad.
6. The animals drink water.Read the text again and write next to the sentences True/False according to the text.
1. She looks after the big animals.
2. Her favorite animals are the tigers.
3. There are four elephants at the zoo.
4. Molly gets up at 6 o'clock.,
5. The lions eat salad.
6. The animals drink water.Read the text again and write next to the sentences True/False according to the text.
1. She looks after the big animals.
2. Her favorite animals are the tigers.
3. There are four elephants at the zoo.
4. Molly gets up at 6 o'clock.,
5. The lions eat salad.
6. The animals drink water.Read the text again and write next to the sentences True/False according to the text.
1. She looks after the big animals.
2. Her favorite animals are the tigers.
3. There are four elephants at the zoo.
4. Molly gets up at 6 o'clock.,
5. The lions eat salad.
6. The animals drink water.Read the text again and write next to the sentences True/False according to the text.
№73. Надо использовать формулу Q=cm (t2-t1) и найти с = Q/ m(t2-t1)
с=19008000/32* (1115-15) =540 Дж/кг*градC
№74. Используя предыдущую формулу, найдем массу m =Q/c (t2-t1)
m=184000/500* (800-600) = 1,84 кг
№ 75. Используем предыдущую формулу дважды. Сначала найдем количество теплоты, необходимое для нагревания алюминиевой кастрюли от 20 градусов до 100 градусов . Затем найдем количество теплоты, необходимое для нагревания воды от 20 град. до 100 град. Прибавим полученные числа и запишем ответ.
Q1=0,5*920*(100-20)=36800 Дж. Q2=2*4200*80=672000 Дж
Q3=36800+672000=708800 Дж.
Имей в виду, что 2л воды =0,002 м3. m=ρV=1000*0,002=2 кг№
аквпикнр5е6пкраеркврин526462еач5кигач5а. 256н6е6а5крнпмннмн7м6пм6пм6пир7ир6мр6м6емнпмнпмнпву4а6ем4аеRead the text again and write next to the sentences True/False according to the text.
1. She looks after the big animals.
2. Her favorite animals are the tigers.
3. There are four elephants at the zoo.
4. Molly gets up at 6 o'clock.,
5. The lions eat salad.
6. The animals drink water.Read the text again and write next to the sentences True/False according to the text.
1. She looks after the big animals.
2. Her favorite animals are the tigers.
3. There are four elephants at the zoo.
4. Molly gets up at 6 o'clock.,
5. The lions eat salad.
6. The animals drink water.Read the text again and write next to the sentences True/False according to the text.
1. She looks after the big animals.
2. Her favorite animals are the tigers.
3. There are four elephants at the zoo.
4. Molly gets up at 6 o'clock.,
5. The lions eat salad.
6. The animals drink water.Read the text again and write next to the sentences True/False according to the text.
1. She looks after the big animals.
2. Her favorite animals are the tigers.
3. There are four elephants at the zoo.
4. Molly gets up at 6 o'clock.,
5. The lions eat salad.
6. The animals drink water.Read the text again and write next to the sentences True/False according to the text.
1. She looks after the big animals.
2. Her favorite animals are the tigers.
3. There are four elephants at the zoo.
4. Molly gets up at 6 o'clock.,
5. The lions eat salad.
6. The animals drink water.
Объяснение:
мнас5ас4аснач5км6кв5
№73. с=540 Дж/кг*градC
№ 74. m=1,84 кг
№75. Q3=708800 Дж
Объяснение:
№73. Надо использовать формулу Q=cm (t2-t1) и найти с = Q/ m(t2-t1)
с=19008000/32* (1115-15) =540 Дж/кг*градC
№74. Используя предыдущую формулу, найдем массу m =Q/c (t2-t1)
m=184000/500* (800-600) = 1,84 кг
№ 75. Используем предыдущую формулу дважды. Сначала найдем количество теплоты, необходимое для нагревания алюминиевой кастрюли от 20 градусов до 100 градусов . Затем найдем количество теплоты, необходимое для нагревания воды от 20 град. до 100 град. Прибавим полученные числа и запишем ответ.
Q1=0,5*920*(100-20)=36800 Дж. Q2=2*4200*80=672000 Дж
Q3=36800+672000=708800 Дж.
Имей в виду, что 2л воды =0,002 м3. m=ρV=1000*0,002=2 кг№
Температура кипения воды 100 град