По теореме синусов MK/sinN= MN/sinK
5√6/sin60°=MN/sin45°
MN=2*5√6*√2/(√3*2)=10
sinА=√3√2/(2√2)=√3/2
∠А = 60°
По теореме синусов MK/sinN= MN/sinK
5√6/sin60°=MN/sin45°
MN=2*5√6*√2/(√3*2)=10
sinА=√3√2/(2√2)=√3/2
∠А = 60°