В треугольнике АВС угол А= альфа >90, угол В=бетта, высота СD равна h.
а) Найдите сторону АВ и радиус R описанной окружности
б) Вычислите значение R, если альфа=135, h=3см, бетта=30
2. Хорда окружности равна альфа и стягивает дугу в 60 градусов. Найдите: а) длину дуги б) площадь сектора, ограниченного этой дугой и двумя радиусами.

1.danced, opened, took , rained, had , washed, did ,watched ,cleaned ,went, made , was , got ,lived , wrote

2.we didn't go to Moscow last summer.

the children didn't have dinner at 2o'clock yesterday.

they didn't watch film last week/

I didn't get up at 8 o'clock yesterday.

it didn't rain two days ago

Ann didn't live in S.Petersburg last year/

She didn't read an untersting book the day before  yesterday.

I didn't my homework after school yesterday.

3.where  the children play in the garden yesterday?

did Tom write a latter three days ago&

What father cook dinneh yesterday&

Who mother go  to work by bus yesterday?

When we have a bath the day before yesterday?

Why Nick come home in the aafternoon?

What grandmother make tea in the morning?

4.1 We didn't have lunch at 1o'clock yesterday.Did we have lunch at 1o'clock yesterday? where we have lunch at 1 o'clock  yesterday? Who have lunch at 1 o'clock yesterday?

4.2 It didn't show last week.Did it show last week? Where it show last week? Who ishow last week?

5/1 I halped the mom yesterday.

5/2 where you live last month?

5/3 Did they wake up at 7 am ?

5/4 We didn't go to school yesterday

5/5Who watch the TV on Sunday ?

в конус вписана пирамида КАВСД, К-вершина (совпадает с вершиной конуса), АВСД-квадрат, О-центр квадрат., центр описанной окружности, КО-высота конуса-высота пирамиды-15, ОС=ОА=ОД=OB=8-радиус конуса,

АС=2*ОА=2*8=16,

треугольник АКО прямоугольный,

АК-боковое ребро пирамиды-корень (КО в квадрате+ОА в квадрате)=корень(225+64)=17

треугольник АСД прямоугольный,

АД=ДС=корень(AC в квадрате/

2)=корень(256/2)=8*корень2= сторона

Основания

площадь

АВСД=АД*ДС=8*корень2*8*корень2=128

проводим перпендикуляр ОН на АД,

OH=1/2ДС=8*корень2/2=4*корень2,

проводим апофему КН на АД, треугольник КОН прямоугольный, KH=корень(КО в квадрате+ОН в квадрате)=корень(225+32)=корень257 - апофема

боковая поверхность

пирамиды=1/2*периметрАВСД*KH=1/2*4*8*к корень 2 корень 257-16 корень 514