Нужно перевести код с C++ на Python #include using namespace std; int a[100][100];main() { freopen("input.txt","r",stdin); int w,h,n,i,j,k,x1,y1,x2,y2,s=0; cin>>w>>h>>n; for(i=0;i{ cin>>x1>>y1>>x2>>y2; for(j=x1;jif(a[j][k]==0){s++;a[j][k]=1;}} cout<}
procedure cube(a,b,c,d,e:real); Var p,q,delta,phi,i:real; y:array[1..3] of real; begin p:=(3*a*c-sqr(b))/(3*sqr(a)); q:=(2*power(b,3)-9*a*b*c+27*sqr(a)*d)/(27*power(a,3)); delta:=power(q/2,2)+power(p/3,3); if delta<0 then begin if q<0 then phi:=arctan(sqrt(-delta)/(-q/2)); if q>0 then phi:=arctan(sqrt(-delta)/(-q/2))+pi; if q=0 then phi:=pi/2; y[1]:=2*sqrt(-p/3)*cos(phi/3); y[2]:=2*sqrt(-p/3)*cos(phi/3+(2*pi)/3); y[3]:=2*sqrt(-p/3)*cos(phi/3+(4*pi)/3); var x:=seq(y[1]-b/(3*a),y[2]-b/(3*a),y[3]-b/(3*a)); write(x.where(x -> x<>e).where(x -> frac(x)=0).where(x -> x>=0).Where(x -> x<=1000).Distinct.Count); end; if delta>0 then begin var arsom:=range(0,1000).Where(x->(a*power(x,3)+b*x*x+c*x+d)/(x-e)=0); write(arsom.Count); {Мы не виноваты, Паскаль не может в комплексные числа} end; if delta=0 then begin y[1]:=2*power(-q/2,1/3); y[2]:=-power(-q/2,1/3); var x:=seq(y[1]-b/(3*a),y[2]-b/(3*a)); write(x.where(x -> x<>e).where(x -> frac(x)=0).where(x -> x>=0).Where(x -> x<=1000).Distinct.Count); end; end;
procedure square(a,b,c,e:real); Var d:real; begin d:=sqr(b)-4*a*c; if d<0 then writeln('0'); if d>0 then begin var x:=arr((-b+sqrt(d))/(2*a),(-b-sqrt(d))/(2*a)); write(x.where(x -> x<>e).where(x -> frac(x)=0).where(x -> x>=0).Where(x -> x<=1000).Distinct.Count); end; if d=0 then begin var x:=arr(-b/(2*a)); write(x.where(x -> x<>e).where(x -> frac(x)=0).where(x -> x>=0).Where(x -> x<=1000).Distinct.Count); end; end;
procedure common(a,b,e:real); begin var x:=arr(-b/a); write(x.where(x -> x<>e).where(x -> frac(x)=0).where(x -> x>=0).Where(x -> x<=1000).Distinct.Count); end;
procedure awfulvar(e:real); begin if (e>=0) and (e<=1000) then writeln('1000') else writeln('1001'); end;
procedure otherawfulvar(e:real); begin if e<>0 then writeln('1') else writeln('0'); end;
begin read(a,b,c,d,e); if (a<>0) and (b<>0) then cube(a,b,c,d,e); if (a=0) and (b<>0) then square(b,c,d,e); if (a=0) and (b=0) and (c<>0) and (d<>0) then common(c,d,e); if (a=0) and (b=0) and (c=0) and (d=0) then awfulvar(e); if (a=0) and (b=0) and (c<>0) and (d=0) then otherawfulvar(e); if (a=0) and (b=0) and (c=0) and (d<>0) then writeln('0'); end.
x
2
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y
2
=
16
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x + y = 4 (2)
rearrange (2) to y = 4 - x (could do x = 4 - y )
substitute y = 4 - x into (1)
hence:
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2
+
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4
−
x
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2
=
16
⇒
x
2
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16
−
8
x
+
x
2
=
16
and
2
x
2
−
8
x
+
16
−
16
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0
⇒
2
x
2
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8
x
=
0
factor and solve : 2x(x - 4 ) = 0
⇒
x
=
0
,
x
=
4
substitute these values into y = 4 - x , to find corresponding values of y.
x = 0 : y = 4 - 0 = 4 → (0 , 4)
x = 4 : y = 4 - 4 = 0 → (4 , 0 )
These are the points of intersection with the line x +y = 4 and the circle
x
2
+
y
2
=
16
Answer link
Объяснение:
//Pascal ABC.NET 3.1 сборка 1256
Var
a,b,c,d,e:real;
procedure cube(a,b,c,d,e:real);
Var
p,q,delta,phi,i:real;
y:array[1..3] of real;
begin
p:=(3*a*c-sqr(b))/(3*sqr(a));
q:=(2*power(b,3)-9*a*b*c+27*sqr(a)*d)/(27*power(a,3));
delta:=power(q/2,2)+power(p/3,3);
if delta<0 then
begin
if q<0 then
phi:=arctan(sqrt(-delta)/(-q/2));
if q>0 then
phi:=arctan(sqrt(-delta)/(-q/2))+pi;
if q=0 then
phi:=pi/2;
y[1]:=2*sqrt(-p/3)*cos(phi/3);
y[2]:=2*sqrt(-p/3)*cos(phi/3+(2*pi)/3);
y[3]:=2*sqrt(-p/3)*cos(phi/3+(4*pi)/3);
var x:=seq(y[1]-b/(3*a),y[2]-b/(3*a),y[3]-b/(3*a));
write(x.where(x -> x<>e).where(x -> frac(x)=0).where(x -> x>=0).Where(x -> x<=1000).Distinct.Count);
end;
if delta>0 then
begin
var arsom:=range(0,1000).Where(x->(a*power(x,3)+b*x*x+c*x+d)/(x-e)=0);
write(arsom.Count);
{Мы не виноваты, Паскаль не может в комплексные числа}
end;
if delta=0 then
begin
y[1]:=2*power(-q/2,1/3);
y[2]:=-power(-q/2,1/3);
var x:=seq(y[1]-b/(3*a),y[2]-b/(3*a));
write(x.where(x -> x<>e).where(x -> frac(x)=0).where(x -> x>=0).Where(x -> x<=1000).Distinct.Count);
end;
end;
procedure square(a,b,c,e:real);
Var
d:real;
begin
d:=sqr(b)-4*a*c;
if d<0 then writeln('0');
if d>0 then
begin
var x:=arr((-b+sqrt(d))/(2*a),(-b-sqrt(d))/(2*a));
write(x.where(x -> x<>e).where(x -> frac(x)=0).where(x -> x>=0).Where(x -> x<=1000).Distinct.Count);
end;
if d=0 then
begin
var x:=arr(-b/(2*a));
write(x.where(x -> x<>e).where(x -> frac(x)=0).where(x -> x>=0).Where(x -> x<=1000).Distinct.Count);
end;
end;
procedure common(a,b,e:real);
begin
var x:=arr(-b/a);
write(x.where(x -> x<>e).where(x -> frac(x)=0).where(x -> x>=0).Where(x -> x<=1000).Distinct.Count);
end;
procedure awfulvar(e:real);
begin
if (e>=0) and (e<=1000) then writeln('1000') else writeln('1001');
end;
procedure otherawfulvar(e:real);
begin
if e<>0 then writeln('1') else writeln('0');
end;
begin
read(a,b,c,d,e);
if (a<>0) and (b<>0) then cube(a,b,c,d,e);
if (a=0) and (b<>0) then square(b,c,d,e);
if (a=0) and (b=0) and (c<>0) and (d<>0) then common(c,d,e);
if (a=0) and (b=0) and (c=0) and (d=0) then awfulvar(e);
if (a=0) and (b=0) and (c<>0) and (d=0) then otherawfulvar(e);
if (a=0) and (b=0) and (c=0) and (d<>0) then writeln('0');
end.
Пример ввода:
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Пример вывода:
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