// PascalABC.NET 3.1, сборка 1200 от 13.03.2016 begin var a:=MatrixRandom(7,7,0,9); var k:=0; for var i:=0 to 6 do begin for var j:=0 to 6 do begin Write(a[i,j]:3); if a[i,j] in [1..5] then Inc(k) end; Writeln end; Writeln('Кол-во элементов на [1,5]: ',k) end.
const n=7; var a:array[1..n,1..n] of integer; i,j,k:integer; begin Randomize; k:=0; for i:=1 to n do begin for j:=1 to n do begin a[i,j]:=Random(10); Write(a[i,j]:3); if a[i,j] in [1..5] then Inc(k) end; Writeln end; Writeln('Кол-во элементов на [1,5]: ',k) end.
#include <iostream>
#include <vector>
#include <set>
#include <cmath>
using namespace std;
bool check(double a, double b, double c){
return !(a >= b + c || b >= a + c || c >= b + c);
}
double square(double a, double b, double c){
double p = (a+b+c)/2;
return sqrt(p * (p-a) * (p-b) * (p-c));
}
bool is_palind(int k){
string s = to_string(k);
for(int i = 0; i < s.length() - i - 1; i++)
if(s[i] != s[s.length()-i-1])
return false;
return true;
}
void solve1(){
vector<double> lines(4);
double ans = -1;
for(auto &i : lines) cin >> i;
for(int i = 0; i < 4; i++)
for(int j = i + 1; j < 4; j++)
for(int k = j + 1; j < 4; j++)
if(check(lines[i],lines[j],lines[k]))
ans = max(ans,square(lines[i],lines[j], lines[k]));
ans == -1 ? cout << "No solution" : cout << ans;
}
void solve2(){
set<int> s;
for(int i = 1000; i < 10000; i++)
if(is_palind(i))
s.insert(i);
int n;
cin >> n;
s.find(n) != s.end() ? cout << n : cout << *upper_bound(s.begin(),s.end(),n);
}
begin
var a:=MatrixRandom(7,7,0,9);
var k:=0;
for var i:=0 to 6 do begin
for var j:=0 to 6 do begin
Write(a[i,j]:3);
if a[i,j] in [1..5] then Inc(k)
end;
Writeln
end;
Writeln('Кол-во элементов на [1,5]: ',k)
end.
Тестовое решение:
2 1 7 3 3 2 7
9 2 9 2 0 5 5
4 2 6 9 4 6 0
1 0 3 5 4 5 9
6 3 6 0 2 0 8
0 8 4 3 2 1 8
6 0 4 4 5 4 0
Кол-во элементов на [1,5]: 27
Вариант "совсем для школы"
const
n=7;
var
a:array[1..n,1..n] of integer;
i,j,k:integer;
begin
Randomize;
k:=0;
for i:=1 to n do begin
for j:=1 to n do begin
a[i,j]:=Random(10);
Write(a[i,j]:3);
if a[i,j] in [1..5] then Inc(k)
end;
Writeln
end;
Writeln('Кол-во элементов на [1,5]: ',k)
end.