1. Найдите количество вещества (H2O) в воде весом 28 г. 2. Образец железа содержит 9,03 * 1024 атомов. Вычислите количество вещества в этом образце железа.
C2H2+2H2--(kat. Pt)--> C2H6 Объем присоединенного водорода к ацетилену равен разности исходного и конечного объема смесей. V(H2 присоед.)= 56-44.8=11.2 л тогда по уравнению реакции: n(H2 присоед.)= моль n(C2H2)=n(C2H6)=0.25 моль V(C2H2)=V(C2H6)= n*=0.25*22.4=5.6 л В исходной смеси объем водорода равен: V(H2)=56 л (объем исходной смеси) - V(C2H2)=56 л-5.6 л=50.4 л В конечной смеси объем водорода равен: V(H2)=44.8 л-V(C2H6)=44.8 л- 5.6 л =39.2 л ответ: объемы газов в исходной смеси V(C2H2)=5.6 л V(H2)=50.4 л в конечной смеси V(C2H6)=5.6 л V(H2)=39.2 л
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Объем присоединенного водорода к ацетилену равен разности исходного и конечного объема смесей.
V(H2 присоед.)= 56-44.8=11.2 л
тогда по уравнению реакции:
n(H2 присоед.)=
n(C2H2)=n(C2H6)=0.25 моль
V(C2H2)=V(C2H6)= n*
В исходной смеси объем водорода равен:
V(H2)=56 л (объем исходной смеси) - V(C2H2)=56 л-5.6 л=50.4 л
В конечной смеси объем водорода равен:
V(H2)=44.8 л-V(C2H6)=44.8 л- 5.6 л =39.2 л
ответ: объемы газов в исходной смеси V(C2H2)=5.6 л V(H2)=50.4 л
в конечной смеси V(C2H6)=5.6 л V(H2)=39.2 л
EMC2 HAS BEEN A VERY GOOD TEAM FOR 64AM 5 AND IT HAS BEEN AN AMAZING OPPORTUNITY FOR US IN A LONG WAY SINCE WE ARE THERE AR PLAYERS IN THE PLAYOFFS FOR THIS IS A GREAT OPPORTUNITY ii4i4i4u4u4u48474747474u4u4uruyrurururururu3TO and the team that we have played with a team that has 7been 7777777777777777777777777777777777777777777O WIN A TEAM THAT IS A VERY GOOD GAME FOR A TEAM OF PLAYERS THAT ARE GOING THROUGH THIS IS THE ST FOR THE GAME OF THE YEAR BECAUSE IT IS THE BEST GAME IN THE LEAGUE FOR US IN THE LAST THREE GAMES AND WE HAVE TO ADD A 3RD TO THE TOP OF THE GAME AND WE WILL HAVE A CHANCE AT A VERY HIGH SPEED IN YOUR GAME AGAINST A VERY HIGH N9999999999999999999UMBER AND WE ARE NOT A VERY 99