Cu (II) + O2 → Zn + O2 → H2 + N2 (III) → Fe (II) - вопрос №22222210759617 от polinka2002761 22.11.2020 15:16

Question

Химия: Cu (II) + O2 → Zn + O2 → H2 + N2 (III) → Fe (II) + O2 → Fe (III) + O2 → Al + Cl2 → Al + S → Mg+O2= Na +Cl2 = H2 + O2= Al + S = Fe (III)+ Cl2 = Zn + N2 = N2 (III) + O2 = Cu + N2 = Na + H2 = Zn + N2 = N2 (IV) + O2 = Na + N2 =

polinka2002761 · Answer

2Cu+O2=2CuO2Zn+O2=ZnO3H2+N2=2NH32Fe+O2=FeO2Fe+3O2=2Fe2O32Al+3Cl2=2AlCl32Al+3S=Al2S32Mg+O2=2MgO2Na+Cl2=2NaCl2H2+O2=2H2O2Fe+3Cl2=2FeCl33Zn+N2=Zn3N23Cu+N2=Cu3N22Na+H2=2NaHN2+2O2=2NO26Na+N2=2Na3N...