Mr(CaOHCO₃) = 40 + 16 + 1 + 12 + 16 · 3 = 117
ω(Са) = Ar(Ca) ÷ Mr(CaOHCO₃) · 100% = 40 ÷ 117 · 100% ≈ 34,19%
W(Ca) ≈ 34.2%
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Mr(CaOHCO₃) = 40 + 16 + 1 + 12 + 16 · 3 = 117
ω(Са) = Ar(Ca) ÷ Mr(CaOHCO₃) · 100% = 40 ÷ 117 · 100% ≈ 34,19%
W(Ca) ≈ 34.2%
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