CH3-NH2+H2O->CH3NH3OH. n(CH3NH2)=m/M=60/31=1,935моль=n(CH3NH3OH), m(CH3NH3OH,теор)=n*M=1,935*49=94,8г, m(CH3NH3OH,практ)=m(CH3NH3OH,теор)*87%/100%=94,8*87/100=82,5г. ответ: m(CH3NH3OH, практ)=82,5г.
CH3-NH2+H2O->CH3NH3OH. n(CH3NH2)=m/M=60/31=1,935моль=n(CH3NH3OH), m(CH3NH3OH,теор)=n*M=1,935*49=94,8г, m(CH3NH3OH,практ)=m(CH3NH3OH,теор)*87%/100%=94,8*87/100=82,5г. ответ: m(CH3NH3OH, практ)=82,5г.