дано
m(H3PO4) = 9.8 g
m(Na3PO4)-?
3NaOH+H3PO4-->Na3PO4+3H2O
M(H3PO4) = 98 g/mol
n(H3PO4) = m/M = 9.8 / 98 = 0.1 mol
n(H3PO4) = n(Na3PO4) = 0.1 mol
M(Na3PO4) = 164 g/mol
m(Na3PO4) = n*M = 0.1*164 = 16.4 g
ответ 16.4 г
дано
m(H3PO4) = 9.8 g
m(Na3PO4)-?
3NaOH+H3PO4-->Na3PO4+3H2O
M(H3PO4) = 98 g/mol
n(H3PO4) = m/M = 9.8 / 98 = 0.1 mol
n(H3PO4) = n(Na3PO4) = 0.1 mol
M(Na3PO4) = 164 g/mol
m(Na3PO4) = n*M = 0.1*164 = 16.4 g
ответ 16.4 г