дано
m(ZnCL2) = 68 g
m(Zn)-?
Zn+2HCL-->ZnCL2+H2
M(ZnCL2) = 136 g/mol
n(ZnCL2) = m/M = 68 / 136 = 0.5 mol
n(Zn) = n(ZnCL2) = 0.5 mol
M(Zn) = 65 g/mol
m(Zn) = n*M= 0.5 * 65 = 32.5 g
ответ 32.5 г
Объяснение:
дано
m(ZnCL2) = 68 g
m(Zn)-?
Zn+2HCL-->ZnCL2+H2
M(ZnCL2) = 136 g/mol
n(ZnCL2) = m/M = 68 / 136 = 0.5 mol
n(Zn) = n(ZnCL2) = 0.5 mol
M(Zn) = 65 g/mol
m(Zn) = n*M= 0.5 * 65 = 32.5 g
ответ 32.5 г
Объяснение: