2al+6hcl=2alcl3+3h2
n(alcl3)=2/6n(hcl)=1/3n(hcl)=1/3*0.6=0.2моль
m(alcl3)=n(alcl3)*M(alcl3)=0.2*133.5=26.7г
2al+6hcl=2alcl3+3h2
n(alcl3)=2/6n(hcl)=1/3n(hcl)=1/3*0.6=0.2моль
m(alcl3)=n(alcl3)*M(alcl3)=0.2*133.5=26.7г