1. Основания трапеции равны 30 и 70, площадь трапеции равна 600, а одна из боковых сторон равна 37. Найдите вторую боковую сторону этой трапеции.
2. На клетчатой бумаге с размером клетки 1 см Х 1 см изображен треугольник АВС с вершинами в узлах сетки (см. рисунок). Найдите длину его медианы СМ.
ответ: расстояние между точками.
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1/2 + 1/5 = 5/10 + 2/10 = 7/10
1/2 + 4/5 = 5/10 + 8/10 = 13/10 = 1 3/10
1/2 + 1/8 = 4/8 + 1/8 = 9/8 = 1 1/8
1/2 + 1 1/3 = 3/6 + 8/6 = 11/6 = 1 5/6
1/2 + 1/9 = 9/18 + 2/18 = 11/18
1/2 + 1/3 = 3/6 + 2/6 = 5/6
1/2 + 1/2 = 2/2 = 1
1/2 + 2/3 = 3/6 + 4/6 = 7/6 = 1 1/6
1/2 + 2 1/6 = 3/6 + 2 1/6 = 2 4/6 = 2 2/3
1/2 + 1/7 = 7/14 + 2/14 = 9/14
1/2 + 1/4 = 2/4 + 1/4 = 3/4
1/2 + 2/5 = 5/10 + 4/10 = 9/10
1/2 + 1 1/2 = 1 2/2 = 2
1/2 + 1/10 = 5/10 + 1/10 = 6/10 = 3/5
1/2 + 3/7 = 7/14 + 6/14 = 13/14
Б
1/3 + 3/8 = 8/24 + 9/24 = 17/24
1/3 + 4/9 = 3/9 +4/9 = 7/8
1/3 + 2/3 = 3/3 = 1
1/3 + 5/6 = 2/6 + 5/6 = 7/6 = 1 1/6
1/3 + 7/18 = 6/18 + 7/18 = 13/18
1/3 + 1 1/2 = 2/6 + 1 3/6 = 1 5/6
1/3 + 3/4 = 4/12 + 9/12 = 13/12 = 1 1/12
1/3 + 2/9 = 3/9 + 2/9 = 5/9
1/3 + 2 1/6 =2/6 + 2 1/6 = 2 3/6 = 2 1/2
1/3 + 4/15 = 5/15 + 4/15 = 9/15 = 3/5
1/3 + 1/7 = 7/21 + 3/21 = 10/21
1/3 + 1/6 = 2/6 + 1/6 = 3/6 = 1/2
1/3 + 5/12 = 4/12 + 5/12 = 9/12 = 3/4
1/3 + 1/15 = 5/15 + 1/15 = 6/15 = 2/5
1/3 + 1/2 = 2/6 + 3/6 = 5/6
В
2/5 + 3/10 = 4/10 + 3/10 = 7/10
2/5 + 4/7 = 14/35 + 20/35 = 34/35
2/5 + 1 1/20 = 8/20 + 1 1/20 = 1 9/20
2/5 + 1/2 = 4/10 + 5/10 = 9/10
2/5 + 3/5 = 5/5 = 1
2/5 + 7/15 = 6/15 + 7/15 = 13/15
2/5 + 9/10 = 4/10 + 9/10 = 13/10 = 1 3/10
2/5 + 3/8 = 16/40 + 15/40 = 31/40
2/5 + 1 1/5 = 1 3/5
2/5 + 2/9 = 18/45 + 10/45 = 28/45
2/5 + 1 7/20 = 8/20 + 1 7/20 = 1 15/20 = 1 3/4
2/5 + 7/10 = 4/10 + 7/10 = 11/10 = 1 1/10
2/5 + 2 4/5 = 2 6/5 = 3 1/5
2/5 + 2/3 = 6/15 + 10/15 = 16/15 = 1 1/15
2/5 + 6/25 = 10/25 + 6/25 = 16/25