1257. 1)8x + 7 y + 53 = 0,4x – 5y + 1 = 0;2)7 x + - вопрос №1257187530451027948063218473139 от krmax2002p0bwab 25.05.2022 16:05

Question

Математика: 1257. 1)8x + 7 y + 53 = 0,4x – 5y + 1 = 0;2)7 x + 9y + 48 = 0,6x + 3y + 27 = 0.​

krmax2002p0bwab · Answer

1)8х+7у+53=04х-5у+1=08х+7у=-534х-5у=-1. *(-2)8х+7у=-53-8х+10у=217у=-51-8х+10у=2У=-3Х=-42)7х+9у+48=06х+3у+27=07х+9у=-486х+3у=-27. (*-3)7х+9у=-48-18х-9у=81-11х=337х+9у=-48х=-3у=-3...

1257. 1)8x + 7 y + 53 = 0,4x – 5y + 1 = 0;2)7 x + 9y + 48 = 0,6x + 3y + 27 = 0.​

1257. 1)
8x + 7 y + 53 = 0,
4x – 5y + 1 = 0;
2)
7 x + 9y + 48 = 0,
6x + 3y + 27 = 0.