ответ: x = (arctg(2/3))/2 - π/6 + (πk)/2, k є Z
2+3tg(2x+π/3) =4
3tg(2x+π/3) = 2
tg(2x+π/3) = 2/3
2x + π/3 = arctg(2/3) + πk, k є Z
2x = arctg(2/3) - π/3 + πk, k є Z
x = (arctg(2/3))/2 - π/6 + (πk)/2, k є Z
ответ: x = (arctg(2/3))/2 - π/6 + (πk)/2, k є Z
2+3tg(2x+π/3) =4
3tg(2x+π/3) = 2
tg(2x+π/3) = 2/3
2x + π/3 = arctg(2/3) + πk, k є Z
2x = arctg(2/3) - π/3 + πk, k є Z
x = (arctg(2/3))/2 - π/6 + (πk)/2, k є Z