Combine the sentences using relative pronouns: 1. bob bought the car from a man. the man was the owner of the gallery. …………………………………………………………………………………. 2. the teacher asked me a question. it was taken from a story book. …………………………………………………………………………………. 3. have you employed the man? i recommend him to you last week. …………………………………………………………………………………. 4. the book was very interesting. i borrowed it from the library yesterday. …………………………………………………………………………………. 5. the girls are my classmates. we saw them at the cinema. ………………………………………………………………………………….. 6. alex took the gun out of his pocket. he saw the robbers running down the street. ………………………………………………………………………………….. 7. the students missed the quiz. they came to class late. ………………………………………………………………………………….. 8. the flowers are still fresh. i picked them up this morning. ………………………………………………………………………………….. 9. there was a garden here. it was full of green trees. now there are only two trees. (relative clause / used to) ………………………………………………………………………………….. 10. they played basketball at home. they broke the vase. it was very valuable. (while / relative clause) ………………………………………………………………………………….. 11. gerry works for a company. it makes typewriter. ………………………………………………………………………………….. 12. this is mrs. green. her daughter got married to a drummer. ………………………………………………………………………………….. 13. that man is an artist. i forgot his name. ………………………………………………………………………………….. worksheet 37 subject : relative clauses a) join these sentences using suitable relative pronouns: 1. we have a neighbour. his dog barks a lot. ……………………………………………………………………………… 2. i don’t know most of the people. you invited them for the party. ……………………………………………………………………………… 3. my cousin is a journalist. her job is interesting. ……………………………………………………………………………… 4. that’s the parcel. it came in the mail. ……………………………………………………………………………… 5. do you know the man? i asked him the address. ……………………………………………………………………………… 6. the boy is the travel agent. he is checking the tickets. ……………………………………………………………………………… 7. the gardener’s wife has just had her third baby. she has been married for six years. ……………………………………………………………………………… 8. the horse came in last. you were telling me about it. ……………………………………………………………………………… 9. i can’t remember the town. i was born there. ……………………………………………………………………………… 10. i apologized to the woman. i spilt her coffee. ……………………………………………………………………………… 11. did you mail the letters? they were on my table. ……………………………………………………………………………… 12. the man teaches at the university. you met his daughter last night. ……………………………………………………………………………… 13. we’re studying science. it helps us to find out a lot about the world around us. ……………………………………………………………………………… 14. the man was very rich. he left a big tip for the waiter. ……………………………………………………………………………… 15. the subject interested everyone. you wrote about it last week. ……………………………………………………………………………… 16. mrs. fox belongs to an organization. it assista hospitals. ……………………………………………………………………………… 17. you should go to dr. anderson. he’ll give you a common exam. ……………………………………………………………………………… 18. we met a girl. her name was unusual. ………………………………………………………………………………. 19. the story can’t possibly be true. he told it to us. ………………………………………………………………………………. 20. did you buy the dress? it was very smart and expensive. ………………………………………………………………………………. 21. that’s the dog. it can understand everything. …………
Пошаговое объяснение:
Предположим, что утверждение задачи не верно. Обозначим сумму цифр числа n через S(n). Среди любых 39 последовательных натуральных чисел обязательно найдётся не менее трёх делящихся на 10; пусть a минимальное из них. При этом получаем, что среди данных 39 чисел также есть и a + 1,..., a + 29. Поскольку a делится на 10, то S(a + 1) = S(a) + 1, S(a + 2) = S(a) + 2,..., S(a + 9) = S(a) + 9. Поэтому среди чисел a, a + 1,..., a + 9 не встречается число, сумма цифр которого делится на 11, только если S(a) $ \equiv$ 1 mod 11. При этом если a + 10 не делится на 100, то S(a + 10) = S(a) + 1, а значит, среди чисел a + 10, a + 11,..., a + 19 найдётся такое, что сумма его цифр делится на 11. Получили противоречие. Осталось рассмотреть случай, когда a + 10 делится на 100. Но тогда заметим, что S(a + 20) = S(a + 10) + 1, а значит, аналогично первому случаю среди чисел a + 10, a + 11,..., a + 29 найдётся число, сумма цифр которого делится на 11. Опять получили противоречие, значит, утверждение задачи верно.
Упорядочим выборку :
10,10,12,13,13,14,15,15,15,16,17,18,18,18,18.
Мода (Mo) − величина, наиболее часто встречающаяся в выборке.. Мо=18
Медиана(Ме)- число, которое разделяет выборку на равные части (при четном - среднему арифметическому двух соседних чисел, которые находятся в середине ряда). Ме=15.
Размах ряда чисел - это разница между самым большим и самым маленьким числом.
18-10=8
Среднее значение выборки -среднее арифметическое ряда чисел .
(10*2+12+13*2+14+15*3+16+17+18*4):15=222:15=27,75
Частотная таблица
символ1012131415161718
частота 2 121 3 114
Пошаговое объяснение:
вроде правильно(●'◡'●)