у(х)=-х^(2/3) + 4
y'(x)=-(2/3)x^(2/3 - 1)=-(2/3)*x^(-1/3)
y'(8/27)=-2/3 * (1/∛(8/27)=-2/3 * 3/2= -1 - это ответ.
1/∛(8/27)=1/(2/3)=3/2.
у(х)=-х^(2/3) + 4
y'(x)=-(2/3)x^(2/3 - 1)=-(2/3)*x^(-1/3)
y'(8/27)=-2/3 * (1/∛(8/27)=-2/3 * 3/2= -1 - это ответ.
1/∛(8/27)=1/(2/3)=3/2.