Впарке прямоугольной формы длинной 160 м и шириной 80 м на расстоянии двух м сделана аллея .найдите её переметр.

А) 11/15   × (4/9  ×  15/22) =
= 11/15  ×  4/9  × 15/22 =
= (11*4*15)/(15*9*22) =
=  (11 * (2*2) * 15)  / (15 * 9 * (11*2) ) =
=  (1 * 2  * 1) / (1 * 9 * 1)  =
= 2/9

б) 1/10 × 22 × 30 ×1/11  =
= 1/10  ×  (22/1)  ×  (30/1)  ×  1/11 =
= (1 *  (11*2)  * (3*10)  * 1)   /   ( 10*1*1*11) =
= (2*3)/1  = 6

в)  11/15  ×  5/26   +  5/26  × 2/15 =
= 5/26  ×  (11/15   + 2/15) = 
= 5/26  ×   13/15   = 
= (5*13)/(26*15) = 
= 1/(2*3) = 1/6

г) 5/34 × 7/9   - 5/34  ×4/27  =
= 5/34 × (7/9   - 4/27)  =
= 5/34 × ( 21/27    - 4/27) =
= 5/34  ×  17/27 =
= (5*17)/(34*27) =
= (5*17) /  ( 2*17*27) =
= 5/(2*27) = 5/54

д)49/64 ×8/9  +11/32 ×8/9 - 3/64 × 8/9 =
= 8/9 ×  (49/64 + 11/32  - 3/64 ) =
= 8/9  ×  (49/64   + 22/64  - 3/64 ) =
= 8/9  × 68/64 =
= (8*68)/(9*64) =
=(8*4*17)  / (9 * 8*8) =
= 17/(9*2) = 17/18

4 7/8 + 1 5/8 = 5 12/8= 6 4/8= 6 1/2=6,5
2 7/15 + 3 13/15=5 20/15= 6 5/15= 6 1/3
4 8/13 + 2 6/13=6 14/13= 7 1/13
5 5/12 + 1 11/12=6 16/12= 7 4/12= 7 1/3
6 2/5 - 4 7/9= 32/5 - 43/9= 288/45 - 215/45=73/45= 1 28/45
10 3/4 - 7 = 10 3/4 - 6 4/4= 43/4 - 28/4=15/4=3 3/4=3,75
8 9/13 + 7 12/13= 15 21/13= 16 8/13
5 3/5 - 2 8/11= 75/5 - 30/11= 825/55 - 150/55=675/55= 12 15/55=12 3/11
4 5/11 - 2 8/11= 49/11 - 30/11= 19/11= 1 8/11
2 18/25 + 7 8/25= 9 26/25= 10 1/25= 10,04
8 3/17 - 4 11/17= 139/17 - 79/17=60/17= 3 9/17
6 8/23 - 12/23=146/23 - 12/23= 134/23= 5 19/23
10 3/5 + 6 4/5=16 7/5= 17 2/5= 17,4
5 7/9 + 3 4/9= 8 11/9= 9 2/9
8 3/9 + 1 7/9=9 10/9= 10 1/9
12 7/8 + 3 7/8= 15 14/8= 16 6/8= 16 3/4= 16,75
10 3/7 - 4 5/7=9 10/7 - 4 5/7= 5 5/7