0:00) da o'suvchi. 4. y = arcctgx funksiyaning aniqlanish sohasi
(-2;o), qiymatlar sohasi esa - (0;).
y = arcctgz funksiya (--20:) da kamayuvchi.
D) 1-0.
10. (98-2-3
A)
D) -
5. y = arcsinr va y = arct gr toq funksiyalar,
y = arccosr va y = arcctgx funksiyalar esa juft
ham emas, toq ham emas.
11. (00-9-
funks
sonla
A) 1
12. (98-
1. (99-8-35) Ushbu y
arcsins ! funksiyaning
qiymatlar to'plamini toping.
A) (0:1) B) 1-5; C) -1; 5 + 1
D) (0:1 E) (0)
2. (98-2-38) Ushbu y =
or csin2t funksiyaning aniqlan-
in (+1)
ish sohasini toping.
A) (-; ) B) : 0) (0:3)
D) (0;31 E) T-4:0 u (0:11
3. (99-3-30) Funksiyaning aniqlanish sohasini top-
ing
yoz
C)
13. (0
ki​

1)12a²b³+3a³b²+16b²-a²=3a²b²(4b+a) + (4²b² - a²)=3a²b²(4b+a)+(4b-a)(4b+a)=
   
= (4b+a)(3a²b² + 4b- a)

2) 49c² -14c+1 -21ac+3a =  (49c²-14c+1) -3a(7c - 1) = (7c - 1)²  - 3a(7c - 1) =

=(7c-1)(7c - 1 - 3a)

3)ax²+ay²+x^4+2x²y²+y^4 = a(x²+y²)+(x^4+2x²y²+y^4) = a(x²+y²) +(x²+y²)²=

   = (x²+y²) (a +x²+y²)

4)  27c³-d³+9c²+3cd+d² = [(3c)³-d³]+ (9c²+3cd+d²) =

=[(3c - d)(9c²+3cd+d²)] + (9c²+3cd+d²) = (9c²+3cd+d²) (3c-d+1)

5) b³-2b²-2b+1 =(b³ + 1) - 2b( b+1) = (b+1)(b² -b+1) - 2b(b+1) =

  = (b+1)(b² -b+1-2b) = (b+1)(b² -3b+1)

Х2-21+54=0 теперь находим дискрименант:  D=21^2-54*4=441-216=225/                                                    21-15теперь находим корни:  х1==3                                                     2                                            21+15                                   х2==18                                             2 теперь находим среднее арифметическое:                                   18+3                                                                                                    =10,5                                                                                                           2 ответ: среднее арифметическое 10,5.