Составь математическую модель данной ситуации:
«На стройке работало 5 бригад по m человек в каждой и 4 бригады по n человек в каждой, при этом всего на стройке работало k человек».
(При записи произведения числа и переменной записывай в начале число, а затем переменную кто-нибудь
log a (a^2/b) log a (a^2) - log a (b)
5log (b^2)/a (a^2/b)= 5· = 5· =
log a (b^2)/a log a (b^2)-log a (a)
2- 3 (-1)
= 5 = 5 = -1
2·3 -1 5
2) log 2 (a^1/3) , если log 4 (a^3)=9
log 4 (a^3)=9 ⇔3 log 4 (a)=9 ⇔ log 4 (a)=3
log 4 (a^1/3) (1/3)log 4 (a) 1log 2 (a^1/3) = = = = 2
log 4 (2) log 4 (√4) 1/2
3) lg2.5 если log 4(125) = a
log 4(125) = a ⇔ log 4(5³) =3 log 4(5) =a ⇔ log 4(5)=a/3
log 4 (5/2) log 4 (5)-log 4 (2) a/3-1/2 2a-3lg2.5 = = = =
log 4 (5·2) log 4 (5) +log 4 (2) a/3 +1/2 2a+3
Объяснение:
f'x = (ctg(x^2 × y))' = -1/(sin^2 (x^2 × y)) × (x^2×y)' = -1/(sin^2 (x^2 × y)) × 2 × x × y = - (2×x×y) / (sin^2 (x^2 × y))
f'y = ctg(x^2 × y))' = -1/(sin^2 (x^2 × y)) × (x^2×y)' = -1/(sin^2 (x^2 × y)) × x^2 = -(x^2) / (sin^2 (x^2 × y))
f"xx = ( -(2×x×y) / (sin^2 (x^2 × y)) )' = - (2×x×y)' × 1/ (sin^2 (x^2 × y)) - (2×x×y) × (1/(sin^2 (x^2 × y)))' = - (2×y) / (sin^2 (x^2 × y)) - (2×x×y) × ( -2/(sin^3 (x^2 ×y)) ) × cos(x^2 × y) × 2 × x × y = - (2×y) / (sin^2 (x^2 × y)) + (8×x^2×y^2) × (1/(sin^3 (x^2 ×y)) ) × cos(x^2 × y) = - (2×y) / (sin^2 (x^2 × y)) + ( 8×x^2×y^2 × cos(x^2 × y) ) / (sin^3 (x^2 ×y))
f"yy = (-(x^2) / (sin^2 (x^2 × y)))' = -(x^2) × (-2) × (sin^(-3) (x^2 × y)) × cos (x^2 × y) × x^2 = ( 2 × x^4 × cos (x^2 × y) ) / (sin^3 (x^2 × y))
f"xy = f"yx = - (2×x) / (sin^2 (x^2 × y)) - (2×x×y) / (sin^3 (x^2 × y)) × (-2 × cos(x^2×y) × x^2) = - (2×x) / (sin^2 (x^2 × y)) + 4 (x^3 × y × cos(x^2×y)) / (sin^3 (x^2 × y))