" alt="\frac{4}{a-1} + \frac{3}{a} = \frac{4a+3(a-1)}{a(a-1)} = \frac {4a+3a-3}{a^{2}-a} = \frac{7a-3}{a^{2}-a}" />" />
4/(a-1)+3/a=(4a+3(a-1)) / (a(a-1))=(4a+3a-3) / (a^2-a)=(7a-3)/ (a^2-a)
4/(a-1)+3/a=(4a+3(a-1)) / (a(a-1))=(4a+3a-3) / (a^2-a)=(7a-3)/ (a^2-a)