y = (2x³ - 4x + 2)⁴
y'(x) = [(2x³ - 4x + 2)⁴]' = 4(2x³ - 4x + 2)³ * (2x³ - 4x + 2)' =
= 4(2x³ - 4x + 2)³ * (6x² - 4)
y'(1) = 4 * (2 * 1³ - 4 * 1 +2)³ * (6 * 1² - 4) = 4 * 0³ * 2= 0
ответ : y'(1) = 0
y = (2x³ - 4x + 2)⁴
y'(x) = [(2x³ - 4x + 2)⁴]' = 4(2x³ - 4x + 2)³ * (2x³ - 4x + 2)' =
= 4(2x³ - 4x + 2)³ * (6x² - 4)
y'(1) = 4 * (2 * 1³ - 4 * 1 +2)³ * (6 * 1² - 4) = 4 * 0³ * 2= 0
ответ : y'(1) = 0